Interest Grove

Inflation, rule of 72 & future value calculators

Purchasing power calculator

Inflation doesn't take money out of your pocket; it makes each dollar buy less. See how much less, at a rate you choose or over real history since any year from 1913.

Measure the loss

Educational use only — not financial advice. A rate you type is an assumption for illustration, not a forecast.

After 20 years at 3.00% inflation, $1,000 buys what

$553.68

buys today.

Buying power lost
44.6%
Prices double in
23.4 years
Needed then to match today
$1,806.11
Today$1,000.00Year 5$862.61Year 10$744.09Year 15$641.86Year 20$553.68
What $1,000 buys, in today's money
YearBuys the same asLost so far
5$862.6113.7%
10$744.0925.6%
15$641.8635.8%
20$553.6844.6%

Two ways to measure the loss

Purchasing power is what a sum of money can buy once inflation is taken into account. With a rate you choose, the calculator divides by the growth in prices. Since a past year, it uses actual prices instead: amount × CPI(start) ÷ CPI(end), from the BLS CPI-U annual averages.

Buying power after n years = amount ÷ (1 + i)^ni = yearly inflation rate. "Prices double in" = ln 2 ÷ ln(1 + i) years.

The coins shrink in area with what the money buys. Once prices have doubled, the same notes buy half as much.

Example: at 3% a year, after 20 years $1,000 buys what $553.68 buys today (1,000 ÷ 1.03^20), a loss of 44.6%. Kept as cash from 1980 to 2025, $1,000 bought only what $255.95 bought in 1980.

Sources

Questions

What inflation rate should I enter?

Any rate you want to test; trying two or three shows how much the answer depends on it. For context, the CPI-U rose by about 3.16% a year on average from 1913 to 2025.

Does money in a savings account lose buying power too?

Only when its interest, after any tax, is lower than inflation. The real return calculator compares the two.

Why not just subtract inflation each year?

Because inflation compounds: each year's rise applies to prices that have already risen. Dividing by (1 + i)^n allows for that.